0=4x^2+7x-18

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Solution for 0=4x^2+7x-18 equation:



0=4x^2+7x-18
We move all terms to the left:
0-(4x^2+7x-18)=0
We add all the numbers together, and all the variables
-(4x^2+7x-18)=0
We get rid of parentheses
-4x^2-7x+18=0
a = -4; b = -7; c = +18;
Δ = b2-4ac
Δ = -72-4·(-4)·18
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{337}}{2*-4}=\frac{7-\sqrt{337}}{-8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{337}}{2*-4}=\frac{7+\sqrt{337}}{-8} $

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